Home
Class 11
PHYSICS
The radius of hydrogen atom is ground st...

The radius of hydrogen atom is ground state is `5xx10^(-11)m`. Find the radius of hydrogen atom is fermimetre.(`1fm=10^(-15)m)`

A

`5xx10^(4)fm`

B

`2xx10^(4)m`

C

`5xx10^(2)fm`

D

`5xx10^(6)fm`

Text Solution

Verified by Experts

(a) `:. 10^(-15)m=1fm`
`:.1m=10^(15)fm`
`:. 5xx10^(-11)m=5xx10^(-11)xx10^(15)fm=5xx10^(4)fm`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • TRANSMISSION

    BITSAT GUIDE|Exercise All Questions|38 Videos

  • WAVE MOTION

    BITSAT GUIDE|Exercise BITSAT Archives|8 Videos

Similar Questions

Explore conceptually related problems

The radius of hydrogen atom in its ground state is 5.3 xx 10^(-11)m . After collision with an electron, it is found to have a radius of 21.2 xx 10^(-11)m . What is the principal quantum number of the final state of the atom?

" The radius of hydrogen atom in the ground state is "52.9pm" .The radius of the first excited state of He "^(+)" ion will be "

Knowledge Check

  • The radius of hydrogen atom, in its ground state, is of the order of

    A
    `10^(-8)` cm
    B
    `10^(-6)` cm
    C
    `10^(-5)` cm
    D
    `10^(-4)` cm

  • The radius of the hydrogen atom in its ground state is a_(0) . The radius of a muonic hydrogen atom in which the electron is replaced by an identically charged muon with mass 207 times that of an electron, is a_(mu) equal to

    A
    207 `a_(0)`
    B
    `(a_(0))/(207)`
    C
    `(a_(0))/(sqrt(207))`
    D
    `a_(0)sqrt(207)`

  • The radius of the hydrogen atom in its ground state is 5.3xx10^(-11) m. The principal quantum number of the final state of the atom is

    A
    2
    B
    3
    C
    4
    D
    16

    • Similar Questions

    Explore conceptually related problems

    The radius of hydrogen atom in the ground state is 5.3 xx 10^(-11) m. When struck by an electron, its radius is found to be 21.2 xx 10^(-11) m . The principal quantum number of the final state will be

    The radius of hydrogen atom in its ground state is 5.3 xx 10^(-11)m . After collision with an electron it is found to have a radius of 21.2 xx 10^(-11)m . What is the principle quantum number of n of the final state of the atom ?

    If radius of first orbit of hydrogen atom is 5.29xx10^(-11) m, the radius of fourth orbit will be

    The radius of hydrogen atom in its ground state is 5.3 xx 10^-11 m . After collision with an electron it is found to have a radius of 21.2 xx 10^-11 m . The principal quantum number of the final state of the atom is.

    If radius of first orbit of hydrogen atom is 5.29 ** 10^(-11) m , the radius of fourth orbit will be

    Home
    Profile