If `x=(a sin theta+b cos theta )/(a+b)`, then

Options

A. the dimensions of `x` and `a` are same
B. the dimensions of `a` and `b` are not same
C. `x` is dimensions
D. None of the above

Explanation

(c) `x=(a sin theta + b cos theta)/(a+b)`
`:.[x]=[(a sin theta)/(a+b)]=[(b cos theta)/(a+b)]` or `[x]=` dimensionless