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A particle moves in a straight line, so ...

A particle moves in a straight line, so that after `t` second, the distance `x` from a fixed point `O` on the line is given by `x=(l-2)^(2)(t-5)`. Then

A

after `2s` velocity of particle is zero

B

after `2s`, the particle reaches at `O`

C

the acceleation is negative when `t lt 3s`

D

All of the above

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