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Determine the amount of CaCl(2) (i = 2.4...

Determine the amount of `CaCl_(2)` (i = 2.47) dissolved in 2.5 L of water sucjh that its osmotic pressure is 0.75 atm at `27^(@)C`.

A

1.0 g

B

9.2 g

C

3.42 g

D

2.42 g

Text Solution

Verified by Experts

The correct Answer is:
c

`pi = iCRT pi = "inRT"//V`
`n = (piV)/(iRT) = (0.75atmxx2.5L)/(2.47xx0.0821 L atm K^(-1) mol^(-1)xx300 K)`
`= 0.0308 mol`
Molar mass of `CaCl_(2) = 111 g mol^(-1)`
Amount dissolved `= 0.0308xx111 = 3.42g`
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Knowledge Check

  • What amount of CaCl_2 (i=2.47) is dissolved in 2 litres of water so that its osmotic pressure is 0.5 atm at 27^@ C ?

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