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On passing 3 A of electricity for 50 min...

On passing 3 A of electricity for 50 min, 1.8 g of metal deposits. The equivalent mass of metal is

A

20.5

B

25.8

C

19.3

D

30.7

Text Solution

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The correct Answer is:
To find the equivalent mass of the metal deposited when passing 3 A of electricity for 50 minutes, we can use Faraday's laws of electrolysis. Here’s a step-by-step solution: ### Step 1: Convert Time from Minutes to Seconds We need to convert the time from minutes to seconds because the standard unit of time in electrochemical calculations is seconds. \[ \text{Time in seconds} = 50 \text{ minutes} \times 60 \text{ seconds/minute} = 3000 \text{ seconds} \] ### Step 2: Calculate Total Charge (Q) Using the formula for charge, \( Q = I \times t \), where \( I \) is the current in amperes and \( t \) is the time in seconds. \[ Q = 3 \text{ A} \times 3000 \text{ s} = 9000 \text{ C} \] ### Step 3: Use Faraday's Law to Find Equivalent Mass According to Faraday's law, the equivalent mass of the metal can be calculated using the formula: \[ \text{Equivalent mass} = \frac{\text{Weight of metal deposited}}{\text{Charge (C)}/96500} \] Where: - Weight of metal deposited = 1.8 g - Charge = 9000 C ### Step 4: Substitute Values into the Formula Now, we can substitute the values into the formula: \[ \text{Equivalent mass} = \frac{1.8 \text{ g}}{9000 \text{ C}/96500} \] ### Step 5: Calculate the Equivalent Mass First, calculate \( \frac{9000}{96500} \): \[ \frac{9000}{96500} \approx 0.0932 \] Now, substitute this value back into the equation: \[ \text{Equivalent mass} = \frac{1.8 \text{ g}}{0.0932} \approx 19.3 \text{ g/equiv} \] ### Final Answer The equivalent mass of the metal is approximately **19.3 g/equiv**. ---

To find the equivalent mass of the metal deposited when passing 3 A of electricity for 50 minutes, we can use Faraday's laws of electrolysis. Here’s a step-by-step solution: ### Step 1: Convert Time from Minutes to Seconds We need to convert the time from minutes to seconds because the standard unit of time in electrochemical calculations is seconds. \[ \text{Time in seconds} = 50 \text{ minutes} \times 60 \text{ seconds/minute} = 3000 \text{ seconds} \] ...
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Knowledge Check

  • On passing 3 A of electricity for 50 min, 1.8 g metal deposits. The equivalent mass of metal is

    A
    9.3
    B
    19.3
    C
    38.3
    D
    39.9
  • On passing 3 Ampere of electricity for 50 minutes, 1.8 g metal is deposited. The equivalent mass of metal is

    A
    20.5
    B
    25.8
    C
    19.3
    D
    30.7
  • On passing 9.65 amperes of electricity for 1000 seconds, 2.0 grams of metal deposits . The molar of metal is

    A
    40
    B
    20
    C
    2
    D
    10
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