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Cu^(+) ion is not stable in aqueous solu...

`Cu^(+)` ion is not stable in aqueous solution because because of dispropotionation reaction. `E^(@)` value of disproportionation of `Cu^(+)` is
`[E_(Cu^(2+)//Cu^(+))^(@)=+ 0.15 V, E_(Cu^(2+)//Cu)^(@)=0.34 V]`

A

`-0.38 V`

B

`+ 0.19 V`

C

`-0.49 V`

D

`+ 0.38 V`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the stability of the `Cu^+` ion in aqueous solution and to calculate the `E^(@)` value for its disproportionation reaction, we can follow these steps: ### Step 1: Write the Disproportionation Reaction The disproportionation reaction for `Cu^+` can be represented as: \[ 2 \, Cu^+ \rightarrow Cu + Cu^{2+} \] In this reaction, one `Cu^+` ion is reduced to `Cu`, while another `Cu^+` ion is oxidized to `Cu^{2+}`. ### Step 2: Identify the Standard Reduction Potentials We are given the following standard reduction potentials: - For the reduction of `Cu^{2+}` to `Cu^+`: \[ E^0_{(Cu^{2+}/Cu^+)} = +0.15 \, V \] - For the reduction of `Cu^{2+}` to `Cu`: \[ E^0_{(Cu^{2+}/Cu)} = +0.34 \, V \] ### Step 3: Write the Half-Reactions 1. The reduction half-reaction for `Cu^{2+}` to `Cu^+`: \[ Cu^{2+} + e^- \rightarrow Cu^+ \quad (E^0 = +0.15 \, V) \] 2. The oxidation half-reaction for `Cu^+` to `Cu^{2+}` (reverse the sign): \[ Cu^+ \rightarrow Cu^{2+} + e^- \quad (E^0 = -0.15 \, V) \] ### Step 4: Calculate the Overall Cell Potential To find the overall cell potential for the disproportionation reaction, we can add the potentials of the two half-reactions: \[ E^0_{cell} = E^0_{reduction} + E^0_{oxidation} \] Substituting the values: \[ E^0_{cell} = (+0.34 \, V) + (-0.15 \, V) \] \[ E^0_{cell} = +0.34 \, V - 0.15 \, V = +0.19 \, V \] ### Step 5: Conclusion on Stability Since the overall cell potential for the disproportionation reaction is positive (`+0.19 V`), this indicates that the reaction is spontaneous. Therefore, the `Cu^+` ion is not stable in aqueous solution as it will tend to disproportionate into `Cu` and `Cu^{2+}`. ### Final Answer The `Cu^+` ion is unstable in aqueous solution due to its tendency to undergo disproportionation, and the calculated standard cell potential for this reaction is `+0.19 V`. ---

To determine the stability of the `Cu^+` ion in aqueous solution and to calculate the `E^(@)` value for its disproportionation reaction, we can follow these steps: ### Step 1: Write the Disproportionation Reaction The disproportionation reaction for `Cu^+` can be represented as: \[ 2 \, Cu^+ \rightarrow Cu + Cu^{2+} \] In this reaction, one `Cu^+` ion is reduced to `Cu`, while another `Cu^+` ion is oxidized to `Cu^{2+}`. ### Step 2: Identify the Standard Reduction Potentials ...
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Calculate equilibrium constant for tha disproportionation reaction : 2Cu^(2+)(aq)rarrCu(s)+Cu^(2+)(aq)" at " 25^(@)C ("Given " E_((Cu^(+)//Cu))^(@)=0.52 V, E_((Cu^(2+)//Cu^(+)))^(@)=0.16 V) .

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Knowledge Check

  • Cu^(+) ion is not stable in aqueous solution because of disproportionation reaction. E^(@) value for disproportionation of Cu^(+) is (Given E_(Cu^(2+)//Cu^(+))^(@)=0.15,E_(Cr^(2+)//Cu)^(@)=0.34V )

    A
    `-0.49V`
    B
    `0.19V`
    C
    `-0.38V`
    D
    `0.38V`
  • E_(Cu^(2+)//Cu)^(@)=0.34V E_(Cu^(+)//Cu)^(@)=0.522V E_(Cu^(2+)//Cu^(+))^(@)=

    A
    0.158
    B
    -0.158
    C
    1.182
    D
    -0.182
  • The equilibrium constant for the disproportionation reaction 2Cu^+ (aq) to Cu(s) + Cu^(2+) (aq) + 25^@ C (E^@ Cu^+ //Cu = 0.52 V, E^@ Cu^(2+) =0.16 V) is

    A
    `6xx10^4`
    B
    `6xx10^6`
    C
    `1.2xx10^6`
    D
    `1.2xx10^(-6)`
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