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The specific conductivity of 0.1 N KCl s...

The specific conductivity of `0.1 N KCl` solution is `0.0129 Omega^(-1) cm^(-1)`. The resistane of the solution in the cell is `100 Omega`. The cell constant of the cell will be

A

1.1

B

1.29

C

0.56

D

`2.80`

Text Solution

Verified by Experts

The correct Answer is:
B
Specific conductivity `(k)=1/Rxx` cell constant
Cell constant `=kxxR=0.0129xx100=1.29`
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