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Hardness of water is 200 p p m. The norm...

Hardness of water is `200 p p m`. The normality and molarity of `CaCO_(3)` in the water is

A

`4xx10^(-3) N,2xx10^(-6)M`

B

`4xx10^(-3) N,2xx10^(-6)N`

C

`4xx10^(-3) N,2xx10^(-3)M`

D

`4xx10^(-3) N,1xx10^(-3)M`

Text Solution

Verified by Experts

The correct Answer is:
C
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Explore conceptually related problems

Hardness of water is 200 ppm. The normality and molarity of CaCO_3 in the water is (a). 2xx10^(-6)(N,2xx10^(-6)M (b). 4xx10^(-2)N,2xx10^(-2)M (c). 4xx10^(-3)N,2xx10^(-3)M (d). 4xx10^(-1)N,2xx10^(-1)M

Hardness of a water sample is 100 "ppm" CaCo_(3) . Thus molarity of CaCO_(3) is

Knowledge Check

  • Hardness of water id 200 p p m . The normality and molarity of CaCO_(3) in the water is

    A
    `2xx10^(-6) N, 2xx10^(-6) M`
    B
    `4xx10^(-2) N, 2xx10^(-2) M`
    C
    `4xx10^(-3) N, 2xx10^(-3) M`
    D
    `4xx10^(-1) N, 2xx10^(-1) M`

  • Solution of CaCO_(3) in water forms a

    A
    homogeneous mixture
    B
    heterogeneous mixture
    C
    azeotropic mixture
    D
    None of these

  • Solution of CaCO_(3) , in water forms a

    A
    homogeneous mixture
    B
    heterogeneous mixture
    C
    azeotropic mixture
    D
    None of these

    • Similar Questions

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    Solution of CaCO_3 in water forms a

    Solution of CaCO_3 in water forms a

    Hardness of water sample is 300 ppm CaCO_3 Hence its molarity is:

    Hardness of water is measured in terms of ppm CaCO_(3) . It is the amount in gms of CaCO_(3) present in 10^(6) gms of H_(2)O .In a sample of 10 litre water,0.56 gm of CaO is required to remove temporary hardness of HCO_(3)^(-) . Permanent hardness due to SO_(4)^(2-) and Cl^(-) of C^(2+) and Mg^(2+) and is removed y the addition of Na_(2)CO_(3) . Temperature hardness is due to HCO_(3)^(-) of Ca^(2+) and Mg^(2+) . It is removed by the addition of CaO. Ca(HCO_(3))_(2)+CaOrarr2CaCO_(3)+H_(2)O massof CaO required to precipitate 2 gm of CaCO_(3) is

    Permanent hardness is due to SO_(4)^(2-) and Cl^(-) of Ca^(2+) and Mg^(2+) in water and are removed by adding Na_(2)CO_(3) as Ca^(2+)+Na_(2)CO_(3)rarr CaCO_(3)+2NA^(+) . If degree of hardness is 100 ppm, then amount of Na_(2)CO_(3) required to soften 10l of hard water is :

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