Find the quantity of heat required to convert 40 g of ice at `-20^(@)`C into water at `20^(@)`C. Given `L_(ice) = 0.336 xx 10^(6) J/kg.` Specific heat of ice = 2100 J/kg-K
Specific heat of water = 4200 J/kg-K

Explanation

To solve the problem of finding the quantity of heat required to convert 40 g of ice at -20°C into water at 20°C, we will break the process down into three steps: heating the ice to 0°C, melting the ice to water, and then heating the water to 20°C.

### Step 1: Heating the Ice from -20°C to 0°C

1. **Calculate the heat required to raise the temperature of ice from -20°C to 0°C.**
- Formula:
\[
q_1 = m \cdot C_i \cdot \Delta T
...