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Calculate the energy of hydrogen atom in...

Calculate the energy of hydrogen atom in the ground state given that the after Bohr orbit og hydrogen is `5xx10^(-11)m` and electronic charge is `1.6xx10^(-19) C`.

Text Solution

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The correct Answer is:
`-2.304xx10^(-18) J`
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Calculate the energy of the electron in the ground state of the hydrogen atom.

Calculate the frequency of revolution of an electron in a hydrogen atom assuming that the radius of the first Bohr orbit is 5 xx 10^(-11) m. Mass of electron = 9.0 xx 10^(-31) kg , charge of electron = 1.6 xx 10^(-19) C, (1)/(4pi epsilon_(0))=9xx10^(9) SI units.

Knowledge Check

  • The energy of an electron in the nth Bohr orbit of hydrogen atom is

    A
    `-(13.6)/(n^(4))`eV
    B
    `-(13.6)/(n^(3))`eV
    C
    `-(13.6)/(n^(2)) ` eV
    D
    `-(13.6)/(n) ` eV
  • Energy of electron of hydrogen atom in second Bohr orbit is

    A
    `-5.44 xx 10^(-19) J`
    B
    `-5.44 xx 10^(-19) kJ`
    C
    `-5.44 xx 10^(-19) ` cal
    D
    `-5.44 xx 10^(-19) ` eV
  • In first Bohr orbit of hydrogen atom, the velocity of electron would be (given that radius of first Bohr orbit is 0.53xx10^(-10)m)

    A
    `2.2xx10^(6)m//s`
    B
    `3.3xx10^(6)m//s`
    C
    `1.1xx10^(6)m//s`
    D
    `4.4xx10^(6)m//s`
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    Calculate the energy of an electron in the second Bohr's orbit of an excited hydrogen atom the energy of electron in the first Bohr orbit is -2.18 xx 10^(-11) erg

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    In hydrogen atom find magnetic field at center in ground. State if Bohr's radius is r_(0) = 5xx 10^(-11) m.