Calculate the binding energy of helium nucleus `(._(2)^(4)He)` and express the quantity in MeV and J
`{:("Mass of helium nucleus",=,4.0028,am u,),("Mass of proton",=,1.00758,am u,),("Mass of neutron",=,1.00897,am u,):}`

Calculate the binding energy of the lithium atom (._(3)^(7)Li) from the following data: {:("mass of proton",= 1.00759,am u,),("mass of neutron",= 1.00898,am u,),("mass of electron",= 0.00055,am u,),("mass of lithium atom",= 7.01818,am u,):}

Complete the nuclear reaction and calculate the energy released. ._(3)^(7)Li + |H ("proton") rarr ._(2)^(4) He + ? + Q {:("Given that mass of lithium atom ",=,7.01822,am u,),("Mass of proton",=,1.00812,am u,),("Mass of " alpha-"particle",=,4.00390,am u,):}

Calculate the packing fraction of alpha -particle from the following data : Mass of helium nucleus =4.0028 amu Mass of free proton =1.00758 amu Mass of free neutron =1.00897 amu

Find the binding energy of an alpha -particle from the following data. Mass of helium nulceus =4.001235 am u Mass of proton =1.007277 am u Mass of neutron =1.00866 am u (take 1 amu=931.4813 MeV) .

Calculate the binding energy per nucleon of ._(20)^(40)Ca . Given that mass of ._(20)^(40)Ca nucleus = 39.962589 u , mass of proton = 1.007825 u . Mass of Neutron = 1.008665 u and 1 u is equivalent to 931 MeV .

Calculate the binding energy per nucleon of ._(20)Ca^(40) nucleus. Mass of (._(20)Ca^(40)) = 39.962591 am u .

Find the minimum energy that a gamma -ray must have to give rise to an electron -positron pair. {:("Mass of electron",= 0.00055 am u,),("Mass of positron",= 0.00055 am u,):}

Calculte the binding energy per nucleon for ._(10)^(20)Ne,._(26)^(56)Fe and ._(98)^(238)U . Given that mass of neutron is 1.008665 am u , mass of proton is 1.007825 am u , mass of ._(10)^(20)Ne is 19.9924 am u , mass of ._(26)^(56)Fe is 55.93492 am u and mass of ._(92)^(238)U is 238.050783 am u .