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Calculate the amount of energy set free ...

Calculate the amount of energy set free by the annigilation of an electron and a positron. Given that mass of electron `= 0.00055` amu and positron = 0.00055 amu.

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The correct Answer is:
1.0211 MeV
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What is the minimum energy released in the annhilation of an electron positron pair?

The mass of an electron in amu is

Knowledge Check

  • The miniumum amount of energy released in annihilation of electron-Positron is

    A
    `1.02 MeV`
    B
    `0.58 MeV`
    C
    `185 MeV`
    D
    `200 MeV`

  • if an electron and a positron annihilitate , them the energy relasesed is

    A
    `3.2xx10^(-13)J`
    B
    `1.6xx10^(-13)J`
    C
    `4.8xx10^(-13)J`
    D
    `6.4x10^(-13)J`

  • The rest mass energy of electron or positron is (in MeV )

    A
    `0.51`
    B
    `1`
    C
    `1.02`
    D
    `1.5`

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    Calculate the binding energy of the deuteron, which consistss of a proton and a neutron, given that the atomic mass of the deuteron is 2.014102 amu,. Take mass of proton (m_(p))=1.007825 amu, mass of a neutron (m_(n))=1.008665 amu and 1amu=931.5 MeV

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