Home
Class 11
CHEMISTRY
A gas is allowed to expand reversibly un...

A gas is allowed to expand reversibly under adiabatic conditions. What is zero for such a process ?

A

`Delta G`

B

`Delta T`

C

`Delta S`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
`q = 0 Delta S = (q)/(T) = 0`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • THERMODYNAMICS

    NARAYNA|Exercise Level -V|106 Videos

  • THERMODYNAMICS

    NARAYNA|Exercise Level-VI|150 Videos

  • THERMODYNAMICS

    NARAYNA|Exercise Level -I (H.W)|38 Videos

  • STRUCTURE OF ATOM

    NARAYNA|Exercise EXERCISE - IV EXEMPLAR PROBLEMS|24 Videos

Similar Questions

Explore conceptually related problems

1 mole of CO_(2) gas as at 300 K is expanded under reversible adiabatic condition such that its volume becomes 27 times.

A sample of ideal gas undergoes isothermal expansion in a reversible manner from volume V_(1) to volume V_(2) . The initial pressure is P_(1) and the final pressure is P_(2) . The same sample is then allowed to undergoes reversible expansion under adiabatic conditions from volume V_(1) to V_(2) . The initial pressure being same but final pressure is P_(2) . The work of expansion in adiabatic process (w_(adi)) is related to work of expansion in isothermal process (w_(iso)) is

Knowledge Check

  • Calculate the final temperature of the gas, if one mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27^@C and the work done Given (C_V=20J//K)

    A
    100 K
    B
    150 K
    C
    195 K
    D
    255 K

  • One mole of ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27^(@)C . If the work done by the gas in the process is 3 kJ, the final temperature will be equal to (C_(v)=20J//Kmol)

    A
    100 K
    B
    450 K
    C
    150 K
    D
    400 K

  • One mole of ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27^(@)C . If the work done by the gas in the process is 3 kJ, the final temperature will be equal to (C_(v)=20J//Kmol)

    A
    100 K
    B
    450 K
    C
    150 K
    D
    400 K

    • Similar Questions

    Explore conceptually related problems

    One mole of an ideal gas is allowed to expand reversible and adiabatically from a temperatureof 27^(@)C) if the work done during the process is 3 kJ,the final temperature will be equal to (C_(v)=20JK^(-1))

    One mole of an ideal gas is allowed to expand reversibly and adibatically from a temperature of 27^(@)C . If the work done during the process is 3 kJ, then final temperature of the gas is (C_(v)=20 J//K)

    A 3 mol sample of a triatomic ideal gas at 300 K is allowed to expand under isobaric adiabatic condition from 5 L to 40 L. The value of DeltaH is

    A gas (C_(v.m)=(5)/(2)R) behaving ideally was allowed to expand reversibly and adiabatically from 1 liter to 32 liter . It's initial at temperature was 327^(@) C . The molar enthalpy changes ("in "J//"mole") for the process is

    A gas (C_(v.m) = (5)/(2)R) behaving ideally is allowed to expand reversibly and adiabatically from 1 litre to 32 litre. Its initial temperature is 327^(@)C . The molar enthalpy change (in J//mol ) for the process is :

    Home
    Profile