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What is the entropy change for the conve...

What is the entropy change for the conversion of one gram of ice to water at 167 K and one atmospheric pressure ? `[Delta H_("fussion") = 6.025 kJ mol^(-1)]`

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The correct Answer is:
2

`Delta _("fusion") S = (Delta_("fusion")H)/(T_(f)) rArr (6.025 xx 10^(3))/(167) xx (1)/(18)`
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What is entropy change for the conversion of one gram of ice to water at 273 K and one atmospheric pressure? (DeltaH_("fusion")=6.025kJ" "mol^(-1))

What is the entropy change for conversion of one gram of ice to water at 273K and one atmospheric pressure ( Delta _(fus) H = 6.025 kJ mol^(-1)) ?

Knowledge Check

  • The change of energy on freezing 1.00 kg of liquid water of 0^(@)C and 1 atm is : (Delta H _("ice"))_("fusion") = 6. 01 kJ // mol

    A
    `236.7 kJ kg ^(-1)`
    B
    `236.4 kJ kg ^(-1)`
    C
    `-333.4 kJ kg ^(-1)`
    D
    `- 236.7 kJ kg ^(-1)`
  • What is the entropy that takes place in conversion of 1 mol of alpha- tin to 1 mol beta - tin at 17^(@)C , 1 atm pressure if enthalpy of transition is 2.90 kJ mol^(-1) ?

    A
    `1.0 kJ mol^(-1)`
    B
    `7.32 JK^(-1) mol^(-1)`
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    `10JK^(-1)mol^(-1)`
    D
    `100JK mol^(-1)`
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    Calculate the entropy change involved in conversion of one mole ( 18g) of solid ice at 273K to liquid water at the same temperature ( latent heat of fusion =6025J mol^(-1))

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