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As shown in the adjoining figure two cha...

As shown in the adjoining figure two charge particles each having charge `q` and mass `m` and `d` distance apart from each other. If two particle in equilibrium under the gravitational and electric force, then determine the ratio `q//m`.

A

`10^(-8)`

B

`10^(-10)`

C

`10^(10)`

D

none

Text Solution

Verified by Experts

(b) Condition for equilibrium `F_(e)=F_(q)`
`(kq^(2))/(d^(2))=(Gm^(2))/(d^(2))`
`implies1/(4piepsilon_(0))(q^(2))/(d^(2))=(Gm^(2))/(d^(2))`
or `(q^(2))/(m^(2))=G(4piepsilon_(0))`
`q/m=sqrt((Gxx4piepsilon_(0)))/1`
`=sqrt((6.67xx10^(-17))/(9xx10^(9)))=10^(-10)`
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Knowledge Check

  • Two charged particles each having a charge +q and mass m are kept at a distance d. if they are in equilibrium under the gravitational force and the electric force between them, then the ratio q/m or specific charge of each particle is

    A
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    C
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    D
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  • Two particles , each of mass m and carrying charge Q , are separated by some distance. If they are in equilibrium under mutual gravitational and electrostatic force then Q//m (in C//kg) is of the order of

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