Which of the following compound can show geometrical isomerism ?

Options

A.
B.
C.
D. None of the above

Explanation

To determine which of the given compounds can show geometrical isomerism, we need to analyze each compound based on the presence of a double bond or a cyclic structure with different substituents.

### Step-by-Step Solution:

1. **Identify the Compounds**: Let's denote the compounds as A, B, and C. We will analyze each one to check for geometrical isomerism.

2. **Analyze Compound A**:
- Compound A has a cyclic structure with substituents.
- Check the substituents: If both substituents attached to the double bond or the ring are the same, geometrical isomerism cannot occur.
- In this case, both substituents on the relevant positions are the same (e.g., CH3 and CH3), so **Compound A cannot show geometrical isomerism**.

3. **Analyze Compound B**:
- Compound B also has a double bond.
- Check the substituents on the double bond: If both substituents are the same, geometrical isomerism cannot occur.
- Here, we find that both substituents are the same (e.g., CH3 and CH3), so **Compound B cannot show geometrical isomerism**.

4. **Analyze Compound C**:
- Compound C has a double bond with different substituents.
- Check the substituents: If there are two different groups attached to each carbon of the double bond, geometrical isomerism can occur.
- In this case, we have CH3 and H on one carbon, and CH3 and H on the other carbon. Since these groups are different, geometrical isomerism is possible.
- The possible isomers are:
- **Cis Isomer**: Both CH3 groups are on the same side.
- **Trans Isomer**: The CH3 groups are on opposite sides.
- Therefore, **Compound C can show geometrical isomerism**.

5. **Conclusion**: Based on the analysis, the compound that can show geometrical isomerism is **Compound C**.

### Final Answer:
The compound that can show geometrical isomerism is **C**.