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Glycin has the structural formula NH(2)-...

Glycin has the structural formula `NH_(2)-CH_(2)-COOH`. Glycine has two dissociation constant for which `K_(a)" and " K_(b)` are `1.6xx10^(-10)" and "K_(b) is 2.5xx10^(12)`. Calculate the isoelectric point of glycine
[Hint : If your answer is 5.12 then fill 0512 in OMR sheet.
If your answer is 8.02 then fill 0802 in OMR sheet]

Text Solution

Verified by Experts

The correct Answer is:
609

`pI=overset(pK_(a1)+pK_(a2))underset(2)_" "pK_(a)=-logK_(a)`
`=(9.7958+2.39)/2=6.09`
`pK_(a1)=-logK_(a)" "pK_(b1)=-logK_(b)`
`pK_(a1)=-log1.6xx10^(-10)" "pK_(b1)=-log2.5xx10^(-12)`
`pK_(a1)=9.79" "pK_(b1)=11.6`
`pK_(a1)+pK_(b1)=14`
`pK_(a2)+11.6=14`
`pK_(a2)=2.3979`
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Knowledge Check

  • The Hydrolysis constant of MX is (Given, K_(b) of MOH is 2 xx 10^(-6) and K_(a) of HX is 5 xx 10^(-7) )

    A
    `10^(2)`
    B
    `10^(-2)`
    C
    `10^(-3)`
    D
    `10^(3)`
  • 0.1 M H_(2)S has K_(1)=10^(-5) & K_(2)=1.5xx10^(-12) . What will be the concentration of S^(-2) in the solution.

    A
    `~~10^(-8)`
    B
    `~~10^(-9)`
    C
    `~~1.5xx10^(-12)`
    D
    `1.2xx10^(-13)`
  • What is the pH of 0.01 M glycine solution? For glycine K_(a_(1)) = 4.5 xx 10^(-3) and Ka_(2) = 1.7 xx 10^(-10) at 298 K

    A
    `3.0`
    B
    `10.0`
    C
    6.1
    D
    7.2
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