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If mercury is used as cathode in the ele...

If mercury is used as cathode in the electrolysis of NaCl solution, the ions discharged at cathode are

A

`H^(+)`

B

`Na^(+)`

C

`OH^(-)`

D

`Cl^(-)`

Text Solution

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The correct Answer is:
To solve the question regarding the ions discharged at the cathode when mercury is used as the cathode in the electrolysis of sodium chloride (NaCl) solution, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Electrolyte**: - The electrolyte in this case is sodium chloride (NaCl) dissolved in water. When NaCl is dissolved, it dissociates into sodium ions (Na⁺) and chloride ions (Cl⁻). 2. **Determine the Electrolysis Process**: - During electrolysis, the ions in the solution migrate towards the electrodes. The sodium ions (Na⁺) move towards the cathode (negative electrode), while the chloride ions (Cl⁻) move towards the anode (positive electrode). 3. **Consider the Nature of the Cathode**: - The cathode is made of mercury (Hg). Mercury is a unique electrode because it can form amalgams with certain metals, including sodium. 4. **Discharge of Ions at the Cathode**: - At the cathode, the sodium ions (Na⁺) are discharged. However, instead of being deposited as solid sodium, they react with the mercury to form sodium amalgam (Na-Hg). This is because sodium is highly reactive and does not exist freely in the elemental state in the presence of water. 5. **Conclusion**: - Therefore, during the electrolysis of NaCl solution with mercury as the cathode, the ions discharged at the cathode are sodium ions (Na⁺), which are discharged in the form of sodium amalgam. ### Final Answer: The ions discharged at the cathode are sodium ions (Na⁺), which form sodium amalgam. ---
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Knowledge Check

  • If Pt is used as cathode in the electrolysis of aqueous NaCl solution, the ion reduced at cathode is :

    A
    `H^+`
    B
    `Na^+`
    C
    `OH^-`
    D
    `Cl^-`
  • On the electrolysis of aqueous solution of sodium sulphate, on cathode we get

    A
    Na
    B
    `H_2`
    C
    `SO_2`
    D
    `SO_3`
  • On the electrolysis for aqueous solution of sodium sulphate , on cathode we get

    A
    `SO_(2)`
    B
    Na
    C
    `SO_(3)`
    D
    `H_(2)`
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