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Standard reduction potential values for ...

Standard reduction potential values for the electrodes are given below.
`Mg^(2+)2e^(-) rarrMg " is" -2.37V`
`Zn^(2+) +2e^(-) rarrZn " is"-0.76V`
`Fe^(2+)+2e^(-)rarrFe " is"-0.44V`
Which of the following statement is correct

A

Zinc will reduce `Fe^(2+)`

B

Zinc will reduce `Mg^(2+)`

C

Mg oxidises Fe

D

Zinc oxidises Fe

Text Solution

Verified by Experts

The correct Answer is:
A
Low SRP will reduce hight SRP ion.
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E^(@) values of Mg^(2+)//Mg is -2.37V, of Zn^(2+)//Zn is -0.76V and Fe^(2+)// Fe is - 0.44V Which of the statement is correct ?

For a reaction Zn^(+2) + 2e^(-) rarr Zn, E^(@) = -0.76V which of the following statement is true? (E = Electrode potential)

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The voltage of a cell whose half-cells are given below is Mg^(2+)+2e^(-)rarrMg(s),E^(@)=-2.37V Cu^(2+)+2e^(-)rarrCu(s),E^(@)=+0.34V standard EMF of the cell is

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The standard electrode potential of the half cells are given below. ZnrarrZn^(2+)+2e^(-):E^(@)=0.76V FerarrFe^(2+)+2e^(-):E^(@)=0.44V The emf of the cell Fe^(2+)+ZnrarrZn^(2+)+Fe is

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