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Standard reduction potential values for ...

Standard reduction potential values for the electrodes are given below.
`Mg^(2+)2e^(-) rarrMg " is" -2.37V`
`Zn^(2+) +2e^(-) rarrZn " is"-0.76V`
`Fe^(2+)+2e^(-)rarrFe " is"-0.44V`
Which of the following statement is correct

A

Zinc will reduce `Fe^(2+)`

B

Zinc will reduce `Mg^(2+)`

C

Mg oxidises Fe

D

Zinc oxidises Fe

Text Solution

Verified by Experts

The correct Answer is:
A
Low SRP will reduce hight SRP ion.
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The standard potentials at 25^@C for the following half reactions are given against them Zn^(2+) +2e^(-) rarr Zn, E^0 =-0 . 762 V Mg^(2+) +2e^(-) rarr Mg, =- 2.37 V . When zinc dust is added to a solution of magnesium chloride .

Knowledge Check

  • E^(@) values of Mg^(2+)//Mg "is" -2.37 V of Zn^(2+)//Zn is -0.76 V and Fe^(2+)//Fe:-0.44 V which of the following statement is correct ?

    A
    Zn will reduce `Fe^(2+)`
    B
    Zn will reduce `Mg^(2+)`
    C
    Mg oxidises Fe
    D
    Zn oxidises Fe

  • E^(@) values of Mg^(2+)//Mg is -2.37V, of Zn^(2+)//Zn is -0.76V and Fe^(2+)// Fe is - 0.44V Which of the statement is correct ?

    A
    Zn will reduce `Fe^(2+)`
    B
    Zn will reducing `Mg^(2+)`
    C
    Mg oxidises Fe
    D
    Zn oxidises Fe

  • For a reaction Zn^(+2) + 2e^(-) rarr Zn, E^(@) = -0.76V which of the following statement is true? (E = Electrode potential)

    A
    E depends upon temperature
    B
    E changes when Zn plate is made bigger in size
    C
    E becomes double if equation is multiplied by2
    D
    `Zn^(+2)` can be reduced to Zn by `H_(2)` gas

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