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Copper sulphate solution (250 ML) was el...

Copper sulphate solution `(250 ML)` was electrolyzed using a platinum anode and a copper cathode. A constant current of `2mA` was passed for `16 mi n`. It was found that after electrolysis the absorbance of the solution was reducted to `50%` of its original value . Calculate the concentration of copper sulphate in the solution to begin with.

Text Solution

Verified by Experts

We known,
Equivalent of `Cu^(2+)` lost during electrolysis
`=(ixxt)/(96500)=(2xx10^(-3)xx16xx60)/(96500)=1.989xx10^(-5)` or mole of `Cu^(2+)` lost during electrolysis `= (1.989xx10^(-5))/(2)`
This value is 50% of the intial concentration of solution.
Thus, initial mole of `CuSO_(4)=(2xx1.989xx10^(-5))/(2)`
`=1.989xx10^(-5)`
Thus, initial concentration of
`CuSO_(4)=(1.989xx10^(-5)xx1000)/(250) [CuSO_(4)]=7.95xx10^(-5)M`
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Copper sulphate solution (250 mL) was electrolysed using a platinum anode and copper cathode. A constant current of 2 mA was passed for 16 minutes. It was found that after electrolysis the absorbance of the solution was reduced to 50% of its original value. Calculate the concentration of copper sulphate in the solution to begin with.

Copper sulphate solution (250 mL) was electrolysed using a platinum electrode (anode) and copper cathode. A constant current 2mA was passed for 16 minute. It was found that after the electrolysis, the absorbance of the solution was reduced to 50\% of its original value. Calculate the concentration of copper sulphate in the solution of begin with

Knowledge Check

  • If 110 g of copper sulphate is present is 550 g of solution , calculate the concentration of solution .

    A
    200%
    B
    20%
    C
    30%
    D
    40%
  • Copper sulphate solution is electrolysed between two platinum electrodes. A current is passed unit 1.6 g of oxygen is liberated at anode. The amount of copper deposited at the cathode during the same period is:

    A
    `6.36 g`
    B
    `63.6g`
    C
    `12.7 g`
    D
    `3.2g`
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    250 mL solutlon of copper sulphate was electrolyzed using a Pl anode and a Cu cathode. A constant current of 2 mA was passed for 16 minutes. 1t was found that after electrolysis the absorbanco of the solution was reduced to 50\% of its original value. Calculate the concentration of copper sulphate in the solution to begin with.

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