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MnO(4)^(-) is intense pint colour, thoug...

`MnO_(4)^(-)` is intense pint colour, though Mn is `(+7)` oxidation state, It is due to

A

oxygen gives colour to it

B

charge transfer when Mn gives its electron to oxygen

C

charge transfer when oxygen gives its electron to Mn making it `Mn(+VI)` hence coloured

D

None is correct.

Text Solution

Verified by Experts

The correct Answer is:
C
Mn is in `+7` o.s. having no unpaired `e^(-)` Pink coloure of `MnO_(4)^(-)` is due to charge transfer.
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MnO_(4)^(-) is off intense pink colour, though Mn is in (+7) oxidation state, it is due to:

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Knowledge Check

  • MnO_(4)^(-) is intense pind colour, though Mn is in (+7) oxidation state. It is due to

    A
    Oxygen gives colour to it
    B
    None of the above to it
    C
    charge transfer when`Mn` gives its electron to oxygen
    D
    Character transfer when oxygen gives its electron to `Mn` making it `Mn (+ VI)` and hence coloured

  • MnO_(4)^(-) is of intense pink colour, though Mn is in (7+) oxidation state, it is due to :

    A
    Oxygen gives colour to it
    B
    Charge transfer when Mn `(7+)` gives its electron to oxygen and oxidise to Mn `(8+)` temporaily
    C
    Charge transfer when oxygen gives its electron to Mn `(7+)` changing in Mn `(6+)` temporaily
    D
    none is correct explanation

  • MnO_(4)^(-) is of intense pink colour, though Mn is in (+7) oxidation state.It is due to:

    A
    Oxygen gives colour to it
    B
    charge transfer when `Mn` gives its electrons to oxygen
    C
    charge transfer when oxygen its electron to `Mn` making it `Mn(+VI)` hence coloured
    D
    None is correct

    • Similar Questions

    Explore conceptually related problems

    The stable oxidation states of Mn are

    The highest oxidation state of Mn is shown by

    Transition metals usually from coloured complexes and d-d transitions (t_(2g)hArre_(g)) are responsible for colour as the energy difference between t_(2g) and e_(g) lies in visible region. But all the coloured ions are not dut to d-d transition but charge transfer bands also play important roles. Charge transfer bands may be of two types. (i) ligand to metal (CTLM) " "(ii) metal to ligand (CTML). Charge transfer transition always produces intense colour as compared to d-d transition. MnO_(4)^(-) is dark purple coloured though Mn is in (+VII) oxidation state with 3d^(@) configuration

    The highest oxidation state shown by Mn is

    Maximum oxidation state of Mn will be in

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