`MnO_(4)^(-)` is intense pint colour, though Mn is `(+7)` oxidation state, It is due to

Options

A. oxygen gives colour to it
B. charge transfer when Mn gives its electron to oxygen
C. charge transfer when oxygen gives its electron to Mn making it `Mn(+VI)` hence coloured
D. None is correct.

Answer

C

Explanation

Mn is in `+7` o.s. having no unpaired `e^(-)` Pink coloure of `MnO_(4)^(-)` is due to charge transfer.