What would happen when a solution of pot...

What would happen when a solution of potassium chromate is treated with an excess of dilute nitric acid ?

`Cr_(2)O_(7)^(2-)` and `H_(2)O` are formed

`CrO_(4)^(2-)` is reduced to `+3` state of Cr

`CrO_(4)^(2-)` is oxidized to `+7` state of Cr

`Cr^(3+)` and `Cr_(2)O_(7)^(2-)` are formed

Text Solution

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The correct Answer is:

(a) When a solution of potassium chromate is treated with an excess of dilute nitric acid. Potassium dichromate and `H_(2)O` are formed.
`2K_(2)CrO_(4)+2HNO_(3)rarrK_(2)Cr_(2)O_(7)+2KNO_(3)+H_(2)O`
Hence `Cr_(2)O_(7)^(-) ` and `H_(2)O` are formed

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What happen when a solution of potassium chromate is treated with an excess of dil. Nitic acid?

`Cr_(2)O_(7)^(2-)` and `H_(2)O` are formed

`Cr_(2)O_(4)^(2-)` is reduced to `0` state of `Cr`

`CrO_(4)^(2-)` is reduced to `+3` state of `Cr`

`Cr^(3+)` and `Cr_(2)O_(7)^(2-)` are formed

When tin is treated with concentrated nitric acid

It is converted into stannous nitrate

It is coverted into stannic nitrate

It is converted into metestannic acid

It becomes passive

What would happen when blood is acidic

Binding of oxygen with haemoglobin increases

Red blood corpuscles are formed in higher number

Binding of oxygen with haemoglobin decreases

There is no change in oxygen binding nor number of RBC