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A chemist opened a cupboard to find four...

A chemist opened a cupboard to find four bottles containing water solutions, each of twhich had lost its lable. Bottles 1,2,3 contained colourless solutions , while bottle 4 contained coloured solution. They were, Copper (II) sulphate, Hydrochloric acid. Lead nitrate, Sodium carbonate. By mixing samples of the contents of the bottles, in pairs. The chemist made the following observations, Bottle `1+` Bottle 2 white precipitate Bottle `1=` Bottle 3 white precipitate
Bottle `1+` Bottle 4 white precipitate
Bottle `2+` Bottle 3 colour less gas evolved
Bottle `2+` Bottle 4 no visible reaction
Bottle `3+` Bottle 4 blue precipitate.
Bottle 3 contains `:`

A

Copper (II) sulphate

B

hydrochloric acid

C

lead nitrate

D

sodium carbonate

Text Solution

Verified by Experts

The correct Answer is:
4

Bottle `2+` Bottle 3 `rarr ` Colour less `(CO_(2))`
`Na_(2)CO_(3)+` acid `rarr Co_(2)(` Colour lessgas )
Bottle `3+` Bottle `4 rarr ` Blue precipitate confirms `Cu^(+2)` in either bottle. Hence
Bottle `3 rarr Na_(2)CO_(3),` Bottle `4 rarr CuSO_(4)`
Bottle `2 rarr HCl, ` So Bottle `1 rarr PbNO_(3)`
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A chemist opened a cupboard to find four bottles containing water solutions, each of twhich had lost its lable. Bottles 1,2,3 contained colourless solutions , while bottle 4 contained coloured solution. They were, Copper (II) sulphate, Hydrochloric acid. Lead nitrate, Sodium carbonate. By mixing samples of the contents of the bottles, in pairs. The chemist made the following observations, Bottle 1+ Bottle 2 white precipitate Bottle 1= Bottle 3 white precipitate Bottle 1+ Bottle 4 white precipitate Bottle 2+ Bottle 3 colour less gas evolved Bottle 2+ Bottle 4 no visible reaction Bottle 3+ Bottle 4 blue precipitate. When bottle 1 is mixed with bottle 4, white precipitate is observed, which is :

A chemist opened a cupboard to find four bottles containing water solutions, each of twhich had lost its lable. Bottles 1,2,3 contained colourless solutions , while bottle 4 contained coloured solution. They were, Copper (II) sulphate, Hydrochloric acid. Lead nitrate, Sodium carbonate. By mixing samples of the contents of the bottles, in pairs. The chemist made the following observations, Bottle 1+ Bottle 2 white precipitate Bottle 1= Bottle 3 white precipitate Bottle 1+ Bottle 4 white precipitate Bottle 2+ Bottle 3 colour less gas evolved Bottle 2+ Bottle 4 no visible reaction Bottle 3+ Bottle 4 blue precipitate. Which of the bottle will give distinctive blue colour with NH_(3) ?

Knowledge Check

  • A chemist opened a cupboard to find four bottles containing water solutions, each of twhich had lost its lable. Bottles 1,2,3 contained colourless solutions , while bottle 4 contained coloured solution. They were, Copper (II) sulphate, Hydrochloric acid. Lead nitrate, Sodium carbonate. By mixing samples of the contents of the bottles, in pairs. The chemist made the following observations, Bottle 1+ Bottle 2 white precipitate Bottle 1= Bottle 3 white precipitate Bottle 1+ Bottle 4 white precipitate Bottle 2+ Bottle 3 colour less gas evolved Bottle 2+ Bottle 4 no visible reaction Bottle 3+ Bottle 4 blue precipitate. When bottle 1 is mixed with bottle 4, white precipitate is observed, which is :

    A
    `PbSO_(4)`
    B
    `PbCO_(3)`
    C
    `PbCl_(2)`
    D
    `Pb(NO_(3))_(2)`
  • A chemist opened a cupboard to find four bottles containing water solutions, each of twhich had lost its lable. Bottles 1,2,3 contained colourless solutions , while bottle 4 contained coloured solution. They were, Copper (II) sulphate, Hydrochloric acid. Lead nitrate, Sodium carbonate. By mixing samples of the contents of the bottles, in pairs. The chemist made the following observations, Bottle 1+ Bottle 2 white precipitate Bottle 1= Bottle 3 white precipitate Bottle 1+ Bottle 4 white precipitate Bottle 2+ Bottle 3 colour less gas evolved Bottle 2+ Bottle 4 no visible reaction Bottle 3+ Bottle 4 blue precipitate. Which of the bottle will give distinctive blue colour with NH_(3) ?

    A
    Bottle 1
    B
    Bottle 2
    C
    Bottle 3
    D
    Bottle 4
  • A chemist opened a cupboard and found four bottles containing water solutions, each of which had lost its label.Bottles 1,2,3 contanied colourless solution, while bottle 4 contained a blue solution.The labels from the bottles were lying scattered on the floor of the cupboard.They were: copper (II) sulphate, Hydrochloric acid lead nitrate , Sodium carbonate By mixing samples of the contents of the bottles, in pairs , the chemist made the following observations : Bottle 1 +Bottle 2 to White precipitate is formed. Bottle 1 +Bottle 3 to White precipitate is formed. Bottle 1 +Bottle 4 to White precipitate is formed. Bottle 2 +Bottle 3 to Colourless and odourless gas is evolved. Bottle 2 +Bottle 4 to No visible reaction is observed. Bottle 3 +Bottle 4 to Blue precipitate is formed. With the help of the above observations answer the following questions. Which of the following bottles will give white precipitate with bottle 1?

    A
    Bottle 2
    B
    Bottle 3
    C
    Bottle 4
    D
    All of these