A chemist opened a cupboard to find four bottles containing water solutions, each of twhich had lost its lable. Bottles 1,2,3 contained colourless solutions , while bottle 4 contained coloured solution. They were, Copper (II) sulphate, Hydrochloric acid. Lead nitrate, Sodium carbonate. By mixing samples of the contents of the bottles, in pairs. The chemist made the following observations, Bottle `1+` Bottle 2 white precipitate Bottle `1=` Bottle 3 white precipitate
Bottle `1+` Bottle 4 white precipitate
Bottle `2+` Bottle 3 colour less gas evolved
Bottle `2+` Bottle 4 no visible reaction
Bottle `3+` Bottle 4 blue precipitate.
Bottle 3 contains `:`
A chemist opened a cupboard to find four bottles containing water solutions, each of twhich had lost its lable. Bottles 1,2,3 contained colourless solutions , while bottle 4 contained coloured solution. They were, Copper (II) sulphate, Hydrochloric acid. Lead nitrate, Sodium carbonate. By mixing samples of the contents of the bottles, in pairs. The chemist made the following observations, Bottle `1+` Bottle 2 white precipitate Bottle `1=` Bottle 3 white precipitate
Bottle `1+` Bottle 4 white precipitate
Bottle `2+` Bottle 3 colour less gas evolved
Bottle `2+` Bottle 4 no visible reaction
Bottle `3+` Bottle 4 blue precipitate.
Bottle 3 contains `:`
Bottle `1+` Bottle 4 white precipitate
Bottle `2+` Bottle 3 colour less gas evolved
Bottle `2+` Bottle 4 no visible reaction
Bottle `3+` Bottle 4 blue precipitate.
Bottle 3 contains `:`
A
Copper (II) sulphate
B
hydrochloric acid
C
lead nitrate
D
sodium carbonate
Text Solution
Verified by Experts
The correct Answer is:
4
Bottle `2+` Bottle 3 `rarr ` Colour less `(CO_(2))`
`Na_(2)CO_(3)+` acid `rarr Co_(2)(` Colour lessgas )
Bottle `3+` Bottle `4 rarr ` Blue precipitate confirms `Cu^(+2)` in either bottle. Hence
Bottle `3 rarr Na_(2)CO_(3),` Bottle `4 rarr CuSO_(4)`
Bottle `2 rarr HCl, ` So Bottle `1 rarr PbNO_(3)`
`Na_(2)CO_(3)+` acid `rarr Co_(2)(` Colour lessgas )
Bottle `3+` Bottle `4 rarr ` Blue precipitate confirms `Cu^(+2)` in either bottle. Hence
Bottle `3 rarr Na_(2)CO_(3),` Bottle `4 rarr CuSO_(4)`
Bottle `2 rarr HCl, ` So Bottle `1 rarr PbNO_(3)`
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