`{:(CHO),("|"),(CH-OH" "overset(2HIO_(4))(rarr)),("|"),(CH_(2)-OH):}` Products obtained in the above reaction are :

Options

A. `HCHO, HCO_(2)H`
B. `HCHO, 2HCO_(2)H`
C. `CO_(2), 2HCO_(2)H`
D. `CO_(2), HCHO, HCO_(2)H`

Explanation

To solve the given problem, we need to analyze the reaction of the compound with periodic acid (HIO4). The compound in question is a diol, which contains two hydroxyl (-OH) groups.

### Step-by-Step Solution:

1. **Identify the Structure**:
The compound can be represented as HO-CH2-CHOH-CH2-OH. This is a 1,2-diol (ethylene glycol).

2. **Reaction with Periodic Acid**:
Periodic acid (HIO4) is known to cleave vicinal diols. In this case, it will cleave the C-C bond between the two carbon atoms that are attached to the hydroxyl groups.

3. **Cleavage of the Diol**:
The reaction will break the bond between the two carbons, resulting in the formation of two carbonyl compounds. The hydroxyl groups will also be oxidized to form carbonyl groups (aldehydes or ketones).

4. **Formation of Products**:
The cleavage will yield two molecules of aldehyde. Specifically, we will get:
- CHO (formaldehyde)
- CHO (formaldehyde)

5. **Final Products**:
The final products of the reaction are:
- Two molecules of formaldehyde (HCHO).

### Summary of Products:
The products obtained from the reaction of the compound with periodic acid (HIO4) are:
- 2 HCHO (formaldehyde).