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The angular momentum of an electron in H...

The angular momentum of an electron in `He^(+)` moving in an orbit is `h//pi`. The debrogile wavelength associated with electron is : [ `a_(0)` is radius of first bohr's orbit of H - atom]

A

`2pi a_(0)`

B

`pi a_(0)`

C

`4pia_(0)`

D

`(pia_(0))/(2)`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • The angular momentum (L) of an electron in a Bohr orbit is gives as:

    A
    `L=(nh)/(2pi)`
    B
    `L=sqrt(l(l+1)(h)/(2pi))`
    C
    `L=(mg)/(2pi)`
    D
    `L=(h)/(4pi)`
  • The angular momentum of the electron in the third orbit of H atom is

    A
    `2.3 xx10^(-34) Js`
    B
    `3.2 xx10^(-34) Js`
    C
    `5.2 xx10^(-34) Js`
    D
    `4.2xx10^(-34) Js`
  • The angular momentum of an electron moving in a Bohr orbit is (h/pi) . What is its energy in the same orbit ?

    A
    `-3.4 eV`
    B
    `-1.51eV`
    C
    `-4.4eV`
    D
    `-6.8eV`
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    What is the angular momentum of an electron in the 3^(rd) Bohr orbit of Hydrogen atom?

    " The angular momentum of an electron is (3h)/(pi) .Then electron revolues in which orbit."

    The value of orbit angular momentum of an electron in the 3^(rd) Bohr orbit of hydrogen will be

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