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The resultant of two forces F(1) and F(2...

The resultant of two forces `F_(1) and F_(2)` is P. If `F_(2)` is reversed , then resultant is Q . Then the value of `(P^(2)+Q^(2))` in terms of `F_(1) and F_(2)` is

Text Solution

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The correct Answer is:
`2(F_(1)^(2)+F_(2)^(2))`
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Knowledge Check

  • Resultant of two vectors vecA and vecB is of magnitude P, If vecB is reversed, then resultant is of magnitude Q. What is the value of P^(2) + Q^(2) ?

    A
    `2(A^(2) + B^(2))`
    B
    `2(A^(2) - B^(2))`
    C
    `A^(2) - B^(2)`
    D
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  • Assertion :- when two non parallel forces F_(1) and F_(2) act on a body. The magnitude of the resultant force acting on the is less than the "sum" of F_(1) and F_(2) Reason :- In a triangle, any side is less then the "sum" of the other two sides.

    A
    If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
    B
    If both Assertion & Reason are True but Reason is not a correct explanation of the Assertiion.
    C
    If Assertion is True but the Reason is False.
    D
    If both Assertion & Reason are False

  • The force constants of two springs are K_(1) and K_(2) . Both are stretched till their elastic energies are equal. If the stretching forces are F_(1) and F_(2) then F_(1) : F_(2) is

    A
    `K_(1) : K_(2)`
    B
    ` K_(2) : K_(1)`
    C
    `sqrt(k_(1)) : sqrt(K_(2))`
    D
    ` K_(1)^(2) : K_(2)^(2)`

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