Home
Class 11
CHEMISTRY
A solid has a bcc structure. If the dist...

A solid has a bcc structure. If the distance of closest approach between the two atoms is `1.73.^(@)A`. The edge length of the cell is

A

20 pm

B

`sqrt(3)//sqrt(2)"pm"`

C

`142.2"pm"`

D

`sqrt(2)"pm"`

Text Solution

Verified by Experts

The correct Answer is:
1
Closest approach between two atoms in bcc=`(sqrt(3)a)/(2)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SOLID STATE

    NARAYNA|Exercise PREVIOUS MAINS QUE|10 Videos

  • SOLID STATE

    NARAYNA|Exercise LEVEL-IV|62 Videos

  • SOLID STATE

    NARAYNA|Exercise PREVIOUS QUE.|8 Videos

  • S-BLOCK ELEMENTS

    NARAYNA|Exercise LEVEL-4|15 Videos

  • SOME BASIC CONCEPTS IN CHEMISTRY STOICHIOMETRY (PART-I)

    NARAYNA|Exercise All Questions|555 Videos

Similar Questions

Explore conceptually related problems

A solid has bcc structure. If the distance of closest approach between the atoms is 1.73 Å . The edge length of the cell is :

A solid has BCC structure. If the distance of closest approach between the two atoms is 1.73 A. The edge length of unit cell is :-

Knowledge Check

  • A solid has a bcc structure. If the distance of closest approach between the two atoms is 1 . 73 Å. The edge length of the cell is :

    A
    200 pm
    B
    `sqrt ((3)/(2))` pm
    C
    `142.2` pm
    D
    `sqrt2` pm

  • A solid has a b.c.c. structure . If the distance of closest approach between the two atoms is 1.73 Å . The edge length of the cell is :

    A
    `sqrt(2)p m`
    B
    `sqrt((3//2))p m`
    C
    `200 p m`
    D
    `142.2p m`

  • A solid has a bcc structure. If the distance of closest approach between the two atoms is 1.73 Å, the edge length of the cell is

    A
    200 pm
    B
    `sqrt3//sqrt2` pm
    C
    142.2 pm
    D
    `sqrt2` pm

    • Similar Questions

    Explore conceptually related problems

    Solid A^(+)B^(-) has a bcc structure .If the distance of closest apporach between two atoms is 173 pm ,the edge length of the cell is:

    A solid A^(+)B^(-) has a body centred cubic structure. The distance of closest approach between the two ions is 0.767Å .The edge length of the unit cell is

    An element occurs in the body centred cubic alttic with cell edge of 300 pm. The density of the element is 8.0 g//cm^(3) . Answer the following the distance fo closest approach between the two atoms of the element in the lattics is

    An ionic solid A^(o+)B^(Θ) crystallizes as an bcc structure. The distance between cation and anion in the lattice is 338 pm . The edge length of cell is

    An ionic solid AB crystallizes as a bcc structure . The distance between cation and anion in the lattice is 338 pm . Calculate the edge length of the unit cell .

    Home
    Profile