The unit cube length for LiCl(NaCl structure) is `5.14overset(@)A`. Assuming anion-anion contract, calculate the ionic radius for chloride ion `overset(@)A` is

Options

A. 0.9
B. 1.8
C. 2.4
D. 3.6

Explanation

Interionic distance of `LiCl=(5.14)/(2)=2.57overset(@)A`
`therefore BC=sqrt(AB^(2)+AC^(2))=sqrt((2.57)^(2)+(2.57)^(2))=3.63`
Radius of `Cl^(o+)` ion =`(!)/(2)xx3.63=1.81overset(@)A`