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The unit cube length for LiCl(NaCl struc...

The unit cube length for LiCl(NaCl structure) is `5.14overset(@)A`. Assuming anion-anion contract, calculate the ionic radius for chloride ion `overset(@)A` is

A

0.9

B

1.8

C

2.4

D

3.6

Text Solution

Verified by Experts

Interionic distance of `LiCl=(5.14)/(2)=2.57overset(@)A`
`therefore BC=sqrt(AB^(2)+AC^(2))=sqrt((2.57)^(2)+(2.57)^(2))=3.63`
Radius of `Cl^(o+)` ion =`(!)/(2)xx3.63=1.81overset(@)A`
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Knowledge Check

  • The edge length of LiCl (NaCl structure) unit cell 514 pm. Assuming anion - anion contact, the ionic radius of Cl^(-) ion is

    A
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  • LiCl has rock salt structure, with an edge length of 6.0Å. If anions are in contact, the ionic radius of chloride ion is

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