Home
Class 12
PHYSICS
The acceleration of a particle which is ...

The acceleration of a particle which is depend on time is given by following function a = 2t + 1 and at time t = 0, x = 1m and ui = 2m/s. Then find out displacement of the particle at t = 3 sec.

Text Solution

AI Generated Solution

To solve the problem, we need to find the displacement of a particle given its acceleration as a function of time, initial position, and initial velocity. Here’s a step-by-step solution: ### Step 1: Understand the given information - Acceleration \( a(t) = 2t + 1 \) - Initial position \( x(0) = 1 \, \text{m} \) - Initial velocity \( u = 2 \, \text{m/s} \) - Time \( t = 3 \, \text{s} \) ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • KINEMATICS

    MOTION|Exercise EXERCISE 1 OBJECTIVE PROBLEMS|103 Videos
  • KINEMATICS

    MOTION|Exercise EXERCISE 2 OBJECTIVE PROBLEMS|75 Videos
  • HYDROSTATIC, FLUID MECHANICS & VISCOSITY

    MOTION|Exercise EXERCISE -3 (SECTION-B) PREVIOUS YEAR PROBLEM|7 Videos
  • KINETIC THEORY OF GASES

    MOTION|Exercise EXERCISE-3 SECTION-B|16 Videos

Similar Questions

Explore conceptually related problems

The acceleration of a particle is given by a = 3t and at t = 0, v = 0, x = 0. The velocity and displacement at t = 2 sec will be-

The acceleration of particle varies with time as shown. (a) Find an expression for velocity in terms of t. (b) Calculate the displacement of the particle in the interval from t = 2 s to t = 4 s. Assume that v = 0 at t = 0.

Knowledge Check

  • The displacement of a particle in time t is given by s=2t^2-3t+1 . The acceleration is

    A
    1
    B
    3
    C
    4
    D
    5
  • The acceleration a of alpha of a particle depends on displacements covered in a time t as a= S + 5 . It is given that initially S=0 m and v=5m//s . Then

    A
    `v= S+5`
    B
    `v= sqrt(S+5)`
    C
    `t= log_(e)((S+5)/(S))`
    D
    `t= log_(e)((S+5)/(5))`
  • A starts from rest, with uniform acceleration a. The acceleration of the body as function of time t is given by the equation a = pt, where p is a constant, then the displacement of the particle in the time interval t = 0 to t=t_(1) will be

    A
    `(1)/(2)pt_(1)^(3)`
    B
    `(1)/(3)pt_(1)^(2)`
    C
    `(1)/(2)pt_(1)^(2)`
    D
    `(1)/(2)pt_(1)^(3)`
  • Similar Questions

    Explore conceptually related problems

    Two particles 1 and 2 start simultaneously from origin and move along the positive X direction. Initial velocity of both particles is zero. The acceleration of the two particles depends on their displacement (x) as shown in fig. (a) Particles 1 and 2 take t_(1) and t_(2) time respectively for their displacement to become x_(0) . Find (t_(2))/(t_(1)) . (b) Which particle will cover 2x_(0) distance in least time? Which particle will cross the point x = 2x_(0) with greater speed? (c) The two particles have same speed at a certain time after the start. Calculate this common speed in terms of a_(0) and x_(0) .

    The acceleration of a particle varies with time t as a=t^(2)+t+2 where t is in seconds. The particle starts with an initial velocity v-3m/s at t=0. find the velocity of the particle at the end of 5s.

    If velocity is depend on time such that v = 4 – 2t. Find out distance travelled by particle from 1 to 3 sec

    The displacement s of a particle at time t is given by s=alpha sin omegat+beta cos omegat then acceleration at time t is

    The velocity of the particle at any time t is given by vu = 2t(3 - t) m s^(-1) . At what time is its velocity maximum?