Home
Class 12
PHYSICS
A student uses a simple pendulum of exac...

A student uses a simple pendulum of exactly `1m` length to determine `g`, the acceleration due ti gravity. He uses a stop watch with the least count of `1sec` for this and record `40 seconds` for `20` oscillations for this observation, which of the following statement `(s) is (are)` true?

A

Error `DeltaT` in measuring T, the time period, is 0.05 second

B

Error `DeltaT` in measuring T, the time period, is 1 second.

C

Percentage error in the determination of g is 5%

D

Percentage error in the determination of g is 2.5%

Text Solution

Verified by Experts

The correct Answer is:
A, C
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ERRORS , THEORY

    MOTION|Exercise EXERCISE 2 (LEVEL -III) (SECTION A)|4 Videos
  • ERRORS , THEORY

    MOTION|Exercise EXERCISE 2 (LEVEL -III) (SECTION B)|4 Videos
  • ERRORS , THEORY

    MOTION|Exercise EXERCISE 2 (LEVEL -I) (SECTION C)|7 Videos
  • ELECTROSTATICS-II

    MOTION|Exercise Exercise - 4 (Level - II)|30 Videos
  • FLUID

    MOTION|Exercise Exercise-4 level-II|5 Videos

Similar Questions

Explore conceptually related problems

The time period T of a simple pendulum depends on length L and acceleration due to gravity g Establish a relation using dimensions.

Three students S_1, S_2 and S_3 perform an experiment for determining the acceleration due to gravity (g) using a simple pendulum. They use different lengths of pendulum and record time for different number of oscillations. The observations are as shown in the table. (Least count of length = 0.1 m least count for time = 0.1 s) If E_1, E_2 and E_3 are the percentage errors in 'g' for students 1, 2 and 3 respectively, then the minimum percentage error is obtained by student no._____.

Knowledge Check

  • A student uses a simple pendulum of exactly 1 m length to determine g, the acceleration due to gravity. He uses a stop watch with the least count of 1 s for this and records 40 s for 20 oscillations. For this observation, which of the following statements is true?

    A
    Error `DeltaT` in measuring T, the time period, is 0.02 seconds.
    B
    Error `DeltaT` in measuring T, the time period, is 1 second
    C
    Percentage error in the deterinination of g is 5%.
    D
    Percentage error in the determination of g is 2.5%.
  • A student uses a simple pendulum of ecactly 1 m length to determine g, the acceleration due to gravity. He uses a stop watch with the least count of 1 s for this and records 40 s for 20 oscillation. For this observation, which of the following statement (s) is (are) true?

    A
    Error `DeltaT` in measuring T, the time period, is 0.05 s
    B
    Error `DeltaT` in measuring T, the time period is, 1 s
    C
    Percentage error in the determination of g is 5%
    D
    Percentage error in the determination of g is 2.5 %
  • Student I ,II , and III perform an experiment for measuring the acceleration due to gravity (g) usinf a simple pendulum. They use lengths of the pendulum and // or record time for different number of oscillations . The observations are shown in the following table . Least count for length = 0.1 cm {:(underset(III)underset(II)underset(I)underset()underset()("Student"),underset(20.0)underset(64.0)underset(64.0)underset((cm))underset("Pendulam")("Length of "),underset(4)underset(4)underset(8)underset((n))underset("n Oscillation")("Number of"),underset(9.0)underset(16.0)underset(16.0)underset((s))underset("Period")("Time")):} Least count for time = 0.1 s . If E_(I), E_(II) , and E_(III) are the percentage errors in g , i.,e., ((Delta g)/( g) xx 100) for students I,II , and III, respectively , then

    A
    `E_(I) = 0`
    B
    ` E_(I) is minimum`
    C
    `E_(I) = E_(II)`
    D
    `E_(II) is maximum`
  • Similar Questions

    Explore conceptually related problems

    A simple pendulum is being used to determine the value of gravitational acceleration g at a certain place. The length of the pendulum is 25.0 cm and a stop watch with 1 s resolution measures the time taken for 40 oscillations to be 50 s. The accuracy in g is:

    A simple pendulum designed on the moon as a seconds pendulum is taken to a planet where the acceleration due to gravity on the surface is twice that on the Earth . If g_("earth") : g_("moon") =6 :1 find the period of oscillation of the pendulum on the planet mentionedabove.

    In an experiment to determine the acceleration due to gravity g , the formula used for the time period of a periodic motion is T = 2pisqrt((7(R - r)/(5g) . The values of R and r are measured to be (60 +- 1)mm and (10 +- 1)mm , repectively. In five successive measurment, the time period is found to be 0.52s, 0.56s,0.57s,0.54s and 0.59s . the least count of the watch used for the measurement of time period is 0.01s . Which of the following satement (s) is (are) true?

    If the time period of oscillation of a pendulum is measured as 2.5 second using a stop watch with the least count (1)/(2) second, then the permissible error in the measurement is

    Student I, II and III perform an experiment for measuring the acceleratioon due to gravity (g) using a simple pendulum . Theu use different lengths of the pedulum and /or record time for different number of oscillations . The observation are shoen in the table . Least count for length =0.1cm Least count for time =0.1s If E_(I) , E_(II) and E_(III) are the percentage errors in g,i.e (Deltag)/(g)xx100 for students I, II, and III respectively ,