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Atomic weight of Ne is 20.2 Ne is a mi...

Atomic weight of ` Ne` is ` 20.2 Ne` is a mixuture of ` Ne^(20)` and ` Ne^(22)`. Relative abunduance fo heavior isotope is :

A

`1:9`

B

`9:1`

C

`70%`

D

`80%`

Text Solution

Verified by Experts

The correct Answer is:
B
Let `W%` of `Ne^(20) = x`
`W%` of `Ne^(22) = 100 - x`
`20.2 = (x xx 20 +(100 -x)22)/(100)`
`2020 = 20x +2200 - 22x`
`2x = 2200 - 2020`
`2x = 180`
`2x = 180`
`x = 90%`
`w%` of `Ne^(20) = 90%`
`w%` of `Ne^(22) = 100 - 90 = 10%`
`Ne^(20): Ne^(20) = 90: 10 = 9:1`
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Knowledge Check

  • If Y=a, a ne 0, the graph for this is :

    A
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