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The number of atoms in 0.004g of magnesi...

The number of atoms in 0.004g of magnesium will be

A

`4 xx 10^(20)`

B

`8 xx 10^(20)`

C

`10^(20)`

D

`6.02 xx 10^(20)`

Text Solution

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The correct Answer is:
To find the number of atoms in 0.004 g of magnesium, we can follow these steps: ### Step 1: Determine the molar mass of magnesium. The molar mass of magnesium (Mg) is approximately 24 g/mol. ### Step 2: Calculate the number of moles of magnesium in 0.004 g. To find the number of moles, we use the formula: \[ \text{Number of moles} = \frac{\text{Given mass}}{\text{Molar mass}} \] Substituting the values: \[ \text{Number of moles} = \frac{0.004 \text{ g}}{24 \text{ g/mol}} = \frac{0.004}{24} \approx 1.6667 \times 10^{-4} \text{ moles} \] ### Step 3: Use Avogadro's number to find the number of atoms. Avogadro's number is \(6.022 \times 10^{23}\) atoms/mol. To find the number of atoms, we multiply the number of moles by Avogadro's number: \[ \text{Number of atoms} = \text{Number of moles} \times \text{Avogadro's number} \] Substituting the values: \[ \text{Number of atoms} = 1.6667 \times 10^{-4} \text{ moles} \times 6.022 \times 10^{23} \text{ atoms/mol} \] Calculating this gives: \[ \text{Number of atoms} \approx 1.004 \times 10^{20} \text{ atoms} \] ### Final Answer: The number of atoms in 0.004 g of magnesium is approximately \(1.004 \times 10^{20}\) atoms. ---

To find the number of atoms in 0.004 g of magnesium, we can follow these steps: ### Step 1: Determine the molar mass of magnesium. The molar mass of magnesium (Mg) is approximately 24 g/mol. ### Step 2: Calculate the number of moles of magnesium in 0.004 g. To find the number of moles, we use the formula: ...
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Knowledge Check

  • If 12 gram of carbon has x atoms, then the number of atoms in 12 grams of magnesium will be :

    A
    x
    B
    2x
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    `x/2`
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  • The number of atoms of 0.03 g of aluminium is nearly (Al = 27)

    A
    `6.68 xx10^(20)`
    B
    `6.68xx10^(21)`
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    `6.68 xx10^(22)`
    D
    `6.68xx10^(23)`
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    A
    `6.02 xx 10^(22)`
    B
    `6.02 xx 10^(23)`
    C
    `12.04 xx 10^(22)`
    D
    `12.04 xx 10^(23)`
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