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Oxidation state of carbon is not zero in...

Oxidation state of carbon is not zero in

A

`CH_(2)O`

B

`C_(6)H_(12)O_(6)`

C

`CH_(2)Cl_(2)`

D

`CHCl_(3)`

Text Solution

Verified by Experts

The correct Answer is:
D
`overset(+2)(CH) Cl_(3)`
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Knowledge Check

  • In which of the following compounds , the oxidation number of carbon is not zero ?

    A
    `C_(12) H_(22)O_(11)`
    B
    `HCHO`
    C
    `CH_3CHO`
    D
    `CH_3COOH`

  • The oxidation number of carbon is zero in

    A
    `HCHO`
    B
    `CH_(2)Cl_(2)`
    C
    `CrO_(5)`
    D
    `C_(12)H_(22)O_(11)`

  • Oxidation state of hydrogen is zero in

    A
    `CaH_(2)`
    B
    `NaH`
    C
    `PdH_(2)`
    D
    `NH_(3)`

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    The valancy of carbons is generally 4 , but its oxidation state may be -4, -2, 0, +2, -1 , etc. In the compounds containing C, H , and O , the oxidation number of C is calculated as Oxidation number of C= (2n_(O)-n_(H))/(n_(C )) Where n_(O), n_(H) and n_(C ) are the numbers of oxygen, hydrogen, and carbons, atoms, respectively. In which of the following compounds is the oxidation state of carbon is zero?

    Assertion : Oxidation state of carbon in its compounds is +4 Reason : An element has a fixed oxidation state.

    Valency and Oxidation number are different for an element. Valency of carbon is generally 4, however, the oxidation state may be -4,-2 0,+2,-1 etc. In the compounds containing carbon. hydrogen and oxygen the oxidation number of carbon can be calculated as "Oxidation number of carbon"=(2n_(O)-n_(H))/(n_(C) Where, n_(H), n_(O) and n_(C) are number of respective atoms Oxidation state of carbon in diamond is:

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