Home
Class 9
MATHS
If n is a natural number then sqrtn is...

If n is a natural number then `sqrtn` is

A

always a natural number

B

always an irrational number.

C

always a rational number

D

may be rational or irrational .

Text Solution

Verified by Experts

The correct Answer is:
D
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • REAL NUMBERS

    SURA PUBLICATION|Exercise ADDITIONAL QUESTIONS AND ANSWERS|49 Videos

  • REAL NUMBERS

    SURA PUBLICATION|Exercise UNIT TEST|19 Videos

  • REAL NUMBERS

    SURA PUBLICATION|Exercise EXERCISE 2.8|18 Videos

  • PROBABILITY

    SURA PUBLICATION|Exercise Unit test (part - B)|4 Videos

  • SET LANGUAGE

    SURA PUBLICATION|Exercise UNIT TEST|20 Videos

Similar Questions

Explore conceptually related problems

The difference between the sum of squares of first n natural numbers and the sum of first n natural numbers is always divisible by 2.

Can the number 6^n , n being a natural number, end with the digit 5? Give reason.

Knowledge Check

  • If n is a natural number then 7^(3n) - 4^(3n) is always divisible by .....................

    A
    11
    B
    3
    C
    33
    D
    both 11 and 3

  • Let n be a natural number. Then the range of the function f(n)=""^(8-n)P_(n-4),4lenle6 , is

    A
    {1, 2, 3, 4}
    B
    {1, 2, 3, 4, 5, 6}
    C
    {1, 2, 3}
    D
    {1, 2, 3, 4, 5}

  • If N is the set of alll natural numbers then which of the following is true

    A
    `f(x) = 3x -2` does not map N to N
    B
    `f(x) =x^2 +1` does not map N to N
    C
    `x to x^2 - 3x +1` does not map N to N
    D
    `x to ( x (x+1))/( 2) ` does not map N to N

    • Similar Questions

    Explore conceptually related problems

    Consider the numbers of the form 4^n where n is a natural number. Check whether there is any value of n for which 4^n ends with zero?

    Define a relation R on the set N of natural numbers by R= {(x, y): y= x+5, x is a natural number less than 4, x, y in N). Depict this relationship using roster form. Write down the domain and the range.

    Prove that ((n^(2))!)/((n!)^(n)) is a natural number for all n in N.

    The variance of first n natural number is:

    The weighted means of of first n natural numbers whose weights are equal to the squares of corresponding numbers is

    Home
    Profile