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Calculate the number of water molecul...

Calculate the number of water molecules present in one drop of water which weights 0.18 g.

Text Solution

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Mass of water = 0.18 g
Number of molecules
`=("Avogadro number "xx " given mass ")/( "Gram molecular mass ")`
`=(6.023xx10^(23) xx0.18 )/( 18)`
`=6.023 xx 10^(21) ` Molecules (or) `= 0.06023 xx 10 ^(23)`
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Knowledge Check

  • The number of molecules present in one gm of hydrogen, is

    A
    `1.5xx10^(23)`
    B
    `30.1xx10^(23)`
    C
    `6.02xx10^(23)`
    D
    `3.01xx10^(23)`

  • The number of water molecules in a drop of water weighing 0.018 g is

    A
    `6.022 xx 10^(26)`
    B
    `6.022 xx 10^(23)`
    C
    `6.022 xx 10^(20)`
    D
    `9.9 xx 10^(22)`

  • The number of water molecules in a drop of water weighing 0.018 g is

    A
    `6.022xx10^(26)`
    B
    `6.022xx10^(23)`
    C
    `6.022xx10^(20)`
    D
    `9.9xx10^(22)`

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