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Given that molar specific heats of gas a...

Given that molar specific heats of gas at' constant pressure and volume as 20.8 J `mol^(-1)K^(-1)` and 12.5`Jmol^(-1)K^(-1)` .Calculate their dirference and the ratio of specific heats of the gas.

Text Solution

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Given :`C_p=20.8Jmol^(-1)K^(-1),C_v=12.5Jmol^(-1)K^(-1)`
Then `C_p-C_v=R=20.8-12.5`
i.e R=8.3`Jmol^(-1)K^(-1)` is known as the universal gas contant.
The ratio of specific heat `gamma=(C_p)/(C_v)=(20.8)/(12.5)`
i.e, `gamma=1.664` which indicates that the gas is monatomic
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Knowledge Check

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