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If the velocity of the electron in Bohr'...

If the velocity of the electron in Bohr's first orbit is `2.19xx 10^(6) ms^(-1)`, calculate the de-Broglie wavelength associated with it.

Text Solution

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`v=2.19xx10^(6)ms^(-1)`
`M=9.11xx10^(-31)kg`
`lamda=h/(mv)=(6.626xx10^(-34)kgm^(2)s^(-1))/(9.11xx10^(-31)kgxx2.19xx10^(6)ms^(-1))`
`lamda=3.32xx10^(-10)m=332`pm
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Knowledge Check

  • The velocity of an electron in Bohr's first orbital of la H-atom is 2.16xx10^(6)ms^(-1) . Its velocity in the second orbit would be

    A
    `1.08xx10^(6)ms^(-1)`
    B
    `0.54xx10^(6)ms^(-1)`
    C
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    D
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  • At 200^(@)C , the velocity of hydrogen molecules is 2.4xx10^(5) cm/sec. In this case the de-Broglie wavelength is about

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    B
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    C
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    D
    `10Å`

  • The de Broglie wavelength of an electron in the first Bohr orbit is

    A
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    B
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    C
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