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In a reversible reaction the rate consta...

In a reversible reaction the rate constants of the forward and the backward reactions are `4.8xx10^(-5)s^(-1)and1.2xx10^(-4)s^(-1)` respectively. Calculate the equilibrium constant.

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`K=k_(1)/k_(2)=(4.8xx10^(-5))/(1.2xx10^(-4))=0.4`
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