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In a reversible reaction the rate consta...

In a reversible reaction the rate constants of the forward and the backward reactions are `4.8xx10^(-5)s^(-1)and1.2xx10^(-4)s^(-1)` respectively. Calculate the equilibrium constant.

Text Solution

Verified by Experts

`K=k_(1)/k_(2)=(4.8xx10^(-5))/(1.2xx10^(-4))=0.4`
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Knowledge Check

  • For a reaction in the equilibrium state, the rate constants for the forward and backward reactions are 2cdot38xx10^(-4) and 8cdot15xx10^(-5) respectively. What is the value of the equilibrium constant?

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    A
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    B
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    C
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