Home
Class 11
CHEMISTRY
An organic compound contains 4.05% hydro...

An organic compound contains 4.05% hydrogen, 24.26% carbon and 71.67% chlorine. Its milecular mass is 98.96. Find its empirical and molecular formula (Atomic mass of `H=1, C=12, Cl=35.45`)

Answer

Step by step text solution for An organic compound contains 4.05% hydrogen, 24.26% carbon and 71.67% chlorine. Its milecular mass is 98.96. Find its empirical and molecular formula (Atomic mass of H=1, C=12, Cl=35.45) by CHEMISTRY experts to help you in doubts & scoring excellent marks in Class 11 exams.

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ANNUAL EXAMINATION QUESTION PAPER SOUTH-2019

    SUBHASH PUBLICATION|Exercise PART-E|7 Videos

  • ANNUAL EXAMINATION QUESTION PAPER SOUTH-2019

    SUBHASH PUBLICATION|Exercise PART-C|9 Videos

  • ANNUAL EXAMINATION QUESTION PAPER SOUTH-2018

    SUBHASH PUBLICATION|Exercise PART-E|7 Videos

  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    SUBHASH PUBLICATION|Exercise THREE MARKS QUESTIONS|28 Videos

Similar Questions

Explore conceptually related problems

A compound contains 4.07% hydrogen, 24.27% Carbon and 71.65%, Chlorine. Its molar mass is 98.96. Calculate is Empiricla and Molecular formulae.

A compound contains 4.07% hydrogen,24.27% carbon and 71.65% chlorine.Its molar mas is 98.96 g.What are its empirical formula and molecular formula?

Knowledge Check

  • An organic compound contains C= 40% H= 13.33% and N= 46.67% . Its emperical formula is

    A
    `C_(2)H_(2)N`
    B
    `C_(3)H_(7)N`
    C
    `CH_(4)N`
    D
    CHN

  • An organic compound contains C = 40%, H = 13.33% and N = 46.67% . Its empirical formula is

    A
    `CH_4N`
    B
    `C_2H_2N`
    C
    CHN
    D
    `C_3H_7N`

  • An organic compound contains C = 40%, H = 13.33% and N-46.67%. Its emperical formula is

    A
    `C_2 H_2 N`
    B
    `C_3 H_7 N`
    C
    `CH_4 N`
    D
    `CHN`

    • Similar Questions

    Explore conceptually related problems

    An orgainc compound contains 43.98% C , 2.09% H , and 37.2% Cl . Calculate its empirical formula.

    A compound contains 32% carbon, 4% hydrogen and rest oxygen. Its vapour density is 75. Calculate the empirical and molecular formula.

    An organic compound on analyis found to contain 92.3 % carbon and 7.7% hydrogen. It vapour density is 39. Find its molecular formula.

    An organic compound contains C=40%,H=13.33% and N=46.67% .Its empirical formula is

    An organic compound contains carbon hydrogen and oxygen . its element analysis C=38.71% , H=9.67% the empirical formula of the compound would be

    Home
    Profile