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NO(2) required for a reaction is produce...

`NO_(2)` required for a reaction is produced by the decomposition of `N_(2)O_(5)` is `"CC"l_(4)` as per the equatiion `2N_(2)O_(5)(g)to4NO_(2)(g)+O_(2)(g)`. The initial concentration fo `N_(2)O_(5)` is `3.00 "mol"L^(-1)` and it is `2.75 "mol"L^(-1)` after 30 minutes. The rate of formation of `NO_(2)` is `4.67xx10^(-x) "mol" L^(-1)"min"^(-1)`. the numerical value of x is __________.

Text Solution

Verified by Experts

The correct Answer is:
2
Rate of disappearance of `N_(2)O_(5)=((3-2.75))/30=25/30xx10^(-2)M"min"^(-1)=(5/6)xx10^(-2)M"min"^(-1)`
Rate of formation of `NO_(2)=2` (rate of disappearance of `N_(2)O_(5)=10/6xx10^(-2)=1.667xx10^(-2)M"min"^(-1)`
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For the reaction 2N_(2)O_(5)(g) to 4NO_(2) (g) + O_(2)(g) , the rate of formation of NO_(2)(g) is 2.8 xx 10^(-3) Ms^(-1) . Calculate the rate of disapperance of N_(2)O_(5)(g) .

The decomposition of N_(2)O_(5) in C Cl_(4) at 318 K is studied by monitoring the concentration of N_(2)O_(5) in the solution. Initially, the concentration of N_(2)O_(5) is 2.4" mol L"^(-1) and after 200 minutes, it is reduced to 2.00" mol L"^(-1). What is the rate of production of NO_(2) during this period in mol L"^(-1)"min"^(-1) ?

Knowledge Check

  • For the first order reaction 2 N_(2)O_(5)(g) to 4 NO_(2) (g) + O_(2)(g)

    A
    The concentration of the reaction decreases exponentially with time
    B
    The half-life of the reaction decreases with increasing temperature
    C
    The half-life of the reaction depends on the initial concentration of the reactant
    D
    The reaction proceeds to 99.6 % completion in eight half-life duration

  • 2N_(2)O_(5)(g) rarr 4NO_(2)(g)+O_(2)(g) The rate of disappearance of N_(2)O_(5)(g) at a certain temperature is 0.016"mol.L"^(-1)"min"^(-1) . What is the rate of formation of NO_(2)(g) (in mol. L^(-1)."min"^(-1) ) at this temperature ?

    A
    `0.0080`
    B
    `0.016`
    C
    `0.032`
    D
    `0.064`

  • For the reactio 2N_(2)O_(5)to4NO_(2)+O_(2) The concentration of N_(2)O_(5) changes from 3.0 M to 2.75 M in 30 minute. Calculate rate of formation of NO_(2)

    A
    0.0167 M `"min"^(-1)`
    B
    0.167 M `"min"^(-1)`
    C
    1.67M `"min"^(-1)`
    D
    none of these

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