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A stick of length L and mass M lies on a...

A stick of length L and mass M lies on a frictionless horizontal surface on which it is free to move in any way. A ball of mass m moving with speed v collides elastically with the stick as shown in the figure. If after the collision the ball comes to rest, then what would be the mass of the ball?

A

m = 2M

B

m = M

C

m = M/2

D

m = M/4

Text Solution

Verified by Experts

The correct Answer is:
D
According to law of conservation of linear momentum
`mv=MV" …(i)"`
According to law of conservation of angular momentum,
`mv.(L)/(2)=(ML^(2))/(12)omega" ….(ii)`
Since, the collision is elastic, therefore `(1)/(2)mv^(2)=(1)/(2)MV^(2)+(1)/(2)lomega^(2)`
Putting the values of `omega` and V in above equation,
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Knowledge Check

  • A stick of length l and mass M lies on a frictionless horizontal surface on which it is free to move in any way. A ball of mass m moving with speed v collides elastically with the stick as shown in the figure. If after the collision ball comes to rest, then what should be the mass of the ball

    A
    m=2M
    B
    m=M
    C
    m=M/2
    D
    m=M/4

  • A Stick of length L and mass M lies on a fnctionless horizontal surface on which it is free to move in any way. A ball of mass m moving with speed v collides elastically with the stick as shownin figure-5.115. If after the collision ball comes to rest, then what should be the mass of the ball ?

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    B
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    `m= M//4`

  • A ball of mass m moving with velocity v , collide with the wall elastically as shown in the figure. After impact the change in angular momentum about P is : .

    A
    `2 mvd`
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    `2 mvd cos theta`
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    `2 mvd sin theta`
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