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If A= [[a,b],[c,d]] and I= [[1,0],[0,1]]...

If `A= [[a,b],[c,d]]` and `I= [[1,0],[0,1]]` then `A^(2)-(a+d)A=`

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Knowledge Check

  • If A^(20) = [(a,b),(c,d)] where A =[(1,1),(0,2)] then a+b+c+d is equal to

    A
    `2^(19)`
    B
    `2^(20)`
    C
    `2^(21)`
    D
    `2^(22)`

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