Show that the straight lines given by `(2+k)x+(1+k)y=5+7k` for different values of `k` pass through a fixed point. Also, find that point.

Explanation

To show that the straight lines given by the equation \((2+k)x + (1+k)y = 5 + 7k\) pass through a fixed point for different values of \(k\), we can follow these steps:

### Step 1: Rearranging the Equation
We start with the equation:
\[ (2+k)x + (1+k)y = 5 + 7k \]
We can rearrange this to group the terms involving \(k\):
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