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Find the equation of the internal bisect...

Find the equation of the internal bisector of angle `B A C` of the triangle `A B C` whose vertices `A ,B ,C` are`(5,2),(2,3)a n d(6,5)` respectively.

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AI Generated Solution

To find the equation of the internal bisector of angle \( BAC \) of triangle \( ABC \) with vertices \( A(5, 2) \), \( B(2, 3) \), and \( C(6, 5) \), we can follow these steps: ### Step 1: Calculate the lengths of sides \( AB \) and \( AC \) Using the distance formula: \[ AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] ...
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Find the equation of the internal bisector of angle BAC of the triangle ABC whose vertices A,B,C are (5,2),(2,3) and (6,5) respectively

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Knowledge Check

  • The equation of the external bisector of angleBAC" to "DeltaABC with vertices A(5, 2), B(2, 3) and C(6, 5) is

    A
    `2x+y+12=0`
    B
    `x+2y-12=0`
    C
    `2x+y-12=0`
    D
    `x-2y-1=0`
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