A star initially has 10^40 deuterons. It...

A star initially has `10^40` deuterons. It produces energy via the processes `._1H^2+_1H^2rarr_1H^3+p` and `._1H^2+_1H^3rarr_2He^4+n`. If the average power radiated by the star is `10^16` W, the deuteron supply of the star is exhausted in a time of the order of
(a) `10^6s` (b) `10^8s` (c) `10^12s`
The masses of the nuclei are as follows
`M(H^2)=2.014` amu, `M(n)=1.008` amu,
`M(p)=1.007` amu,`M(He^4)=4.001`amu

`10^(6)` sec

`10^(8)` sec

`10^(12)` sec

`10^(16)` sec

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A star initially has 10^(40) deuterons it product energy via the process _(1)H^(2) + _(1)H^(2) + rarr _(1) H^(3) + p. and _(1)H^(2) + _(1)H^(3) + rarr _(2) He^(4) + n If the deuteron supply of the average power radiated by the state is 10^(16) W , the deuteron supply of the state is exhausted in a time of the order of . The masses of the nuclei are as follows: M(H^(2)) = 2.014 amu, M(p) = 1.007 amu, M(n) = 1.008 amu, M(He^(4)) = 4.001 amu.

`10^(6) s.`

`10^(8) s.`

`10^(12) s.`

`10^(16) s`.

(a) `10^6s`

(b) `10^8s`

(d) `10^16s`

`10^(6) s`

`10^(8) s`

`10^(12) s`

`10^(16) s`