Name the following halides according to IUPAC system and classify them as alkyl, allyl, benzyl (primary, secondary, tertiary), vinyl or aryl halides:
(i) `(CH_(3))_(2)CHCH(Cl)CH_(3) , (ii) CH_(3)CH_(2)CH(CH_(3))CH(C_(2)H_(5))Cl`
(iii) `CH_(3)CH_(2)C(CH_(3))_(2)CH_(2)I , (iv) (CH_(3))_(3)C CH_(2)CH(Br)C_(6)H_(5)`
(v) `CH_(3)CH(CH_(3))CH(Br)CH_(3) , (vi) CH_(3)C(C_(2)H_(5))_(2)CH_(2)Br`
`(vii) CH_(3)C(Cl)(C_(2)H_(5))CH_(2)CH_(3) , (viii) CH_(3)CH=C(Cl)CH_(2)CH(CH_(3))_(2)`
(ix) `CH_(3)CH=CHC(Br)(CH_(3))_(2) (x) p-ClC_(6)H_(4)CH_(2)CH(CH_(3))_(2)`
(xi) `m-ClCH_(2)C_(6)H_(4)CH_(2)C(CH_(3))_(3) , "(xii)" o-Br-C_(6)H_(4)CH(CH_(3))CH_(2)CH_(3)`

Explanation

To solve the problem of naming the halides according to the IUPAC system and classifying them as alkyl, allyl, benzyl, vinyl, or aryl halides, we will follow a systematic approach for each compound provided in the question.

### Step-by-Step Solution:

1. **(i) `(CH₃)₂CHCH(Cl)CH₃`**
- Structure: Isopropyl group with a chlorine atom on the second carbon.
- Numbering: Start from the end closest to the chlorine: 1 (Cl), 2 (C), 3 (C), 4 (C).
- Name: 2-Chloro-3-methylbutane.
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