Home
Class 12
PHYSICS
A proton is bombarded on a stationary li...

A proton is bombarded on a stationary lithium nucleus. As a result of the collision, two `alpha`-particles are produced. If the direction of motion of the `alpha`-particles with the initial direction of motion makes an angles `cos^-1(1//4)`, find the kinetic energy of the striking proton. Given, binding energies per nucleon of `Li^7` and `He^4` are `5.60` and `7.06 MeV`, respectively.
(Assume mass of proton `~~` mass of neutron).

A

17.28 MeV

B

17.36 MeV

C

17.58 MeV

D

17.44 MeV

Text Solution

Verified by Experts

The correct Answer is:
A
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • JEE MOCK TEST 21

    NTA MOCK TESTS|Exercise PHYSICS|25 Videos

  • JEE MOCK TEST 24

    NTA MOCK TESTS|Exercise PHYSICS|25 Videos

Similar Questions

Explore conceptually related problems

Find the energy of the reaction Li^(7)+prarr2He^(4) if the binding energies per nucleon in Li^(7) and He^(4) nuclei are known to be equal to 5.60 and 7.06 MeV respectively.

What is the binding energy per nucleon in ._2He^4 Given , Mass of ._2He^4 =4.002604 amu Mass of proton =1.007825 amu Mass of neutron =1.008665 amu

Knowledge Check

  • The energy of the reaction Li^(7)+prarr2He^(4) is ( the binding energy per nucleon in Li^(7) and He^(4) nuclei are 5.60 and 7.60 MeV respectively.)

    A
    `17.3 MeV`
    B
    `1.73 MeV`
    C
    `1.46 MeV`
    D
    depends on binding energy of proton

  • Calculate the energy of the reaction , Li^(7) + p to 2 _(2)He^(4) If the binding energy per nucleon in Li^(7) and He^(4) nuclei are 5.60 MeV and 7.06 MeV , respectively .

    A
    19.6 MeV
    B
    2.4 MeV
    C
    8.4 MeV
    D
    17.28 MeV

  • If the binding energy per nucleon in L i^7 and He^4 nuclei are respectively 5.60 MeV and 7.06 MeV . Then energy of reaction L i^7 + p rarr 2_2 He^4 is.

    A
    19.6 MeV
    B
    2.4 MeV
    C
    8.4 MeV
    D
    17.3 MeV

    • Similar Questions

    Explore conceptually related problems

    The binding energy per nucleon from the following data, mass of Li^(7) =7.01653amu mass of proton =1.00759amu mass of neutron = 1.00898 amu is

    The binding energies of deutron (._1H^2) and alpha -particle (._2He^4) are 1.25 and 7.2 MeV/nucleon respectively. Which nucleus is more stable?

    Protons accelerated by a potential difference of 6.8 MV bombard a stationary lithium target. The collision of a proton with a nucleus of Li^(7) isotope results in the birth of two alpha-particles which separate symmetrically with respect to the direction of the proton beam. Find the kinetic energy and the separation angle of the alpha-particles.

    The binding energies of a deutron and an alpha -particle are 1.125,7.2 MeV//"nucleon" respectively. The more stable of the two, is

    A nucleus of mass 220 amu in the free state decays to emit an alpha -particle . Kinetic energy of the alpha -particle emitted is 5.4 MeV. The recoil energy of the daughter nucleus is

    Home
    Profile