Prove that :`1^2+2^2+3^2++n^2=(n(n+1)(2n+1))/6`

Explanation

To prove that the sum of the squares of the first n natural numbers is given by the formula:

\[ 1^2 + 2^2 + 3^2 + \ldots + n^2 = \frac{n(n+1)(2n+1)}{6} \]

we will use the method of mathematical induction.

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