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Prove that :1^2+2^2+3^2++n^2=(n(n+1)(2n+...

Prove that :`1^2+2^2+3^2++n^2=(n(n+1)(2n+1))/6`

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To prove that the sum of the squares of the first n natural numbers is given by the formula: \[ 1^2 + 2^2 + 3^2 + \ldots + n^2 = \frac{n(n+1)(2n+1)}{6} \] we will use the method of mathematical induction. ...
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Statement-1: 1^(2)+2^(2)+....+n^(2)=(n(n+1)(2n+1))/(6)"for all "n in N Statement-2: 1+2+3....+n=(n(n+1))/(2),"for all"n in N

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