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Prove that difference of squares of two distinct odd natural numbers is always a multiple of 8.

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Knowledge Check

  • The difference between the squares of two consécutive odd integers is always divisible by

    A
    8
    B
    7
    C
    6
    D
    3
  • What is the square root of the sum of first 36 odd natural numbers?

    A
    6
    B
    36
    C
    64
    D
    72
  • What is the square root of the sum of first 36 odd natural numbers?

    A
    6
    B
    36
    C
    64
    D
    72
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    Consider the following statements : 1. Unit digit in 17^(174) is 9. 2. Difference of the squares of any two odd numbers is always divisible by 8. 3. Adding 1 to the product of two consecutive odd numbers makes it a perfect-square. Which of the above statements are correct?

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