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The number of terms free from radical si...

The number of terms free from radical sign in the expansion of `(1+3^(1/3)+7^(1/7))^10` is

A

4

B

5

C

6

D

8

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • The number of terms free from radicals in the expansion of (7^(1//3) +11^(1//9))^(6561) is equal to

    A
    715
    B
    725
    C
    730
    D
    750
  • The number of terms which are free from radical signs in the expansion of (x^(1//5)+y^(1//10))^(55) is

    A
    6
    B
    7
    C
    8
    D
    none
  • Number of irrational terms in the binomial expansion of (3^(1//5) +7^(1//3) )^(100) is

    A
    90
    B
    88
    C
    94
    D
    95
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